$\frac{8^7}{8^5}$
$\frac{7}{9\:}\:x\:-\:\frac{5}{3}\:>-2$
$\left(\frac{1}{x^2y^3}\right)^4$
$-1\left(x+1\right)\left(x+6\right)$
$15x^2-9x$
$\frac{2}{3}x-\frac{5}{6}y-z-\frac{1}{2}x+\frac{1}{3}y+\frac{5}{9}z$
$2\cdot2\cdot7$
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