$\left(\frac{x}{4}-5\right)\left(\frac{x}{4}+5\right)$
$\frac{4}{2}\cdot\frac{5}{1}$
$4\left(5x^3y^4z^5\right)$
$\left(x+2\right)\left(x-1\right)\left(x-2\right)$
$121x^2-4y^8$
$\left(5x+9\right)\left(5x-7\right)^2$
$4=-6+f$
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