$\lim_{x\to\infty}\left(\frac{3x^3}{x^2+1}\right)$
$5^3\cdot5$
$\left(x-d\right)^2$
$\left(a^{x^2+7x}\right)$
$x^3y'=secy$
$\left(\cos\left(x\right)+3\sin\left(x\right)\right)^2=5-4\cos\left(2x\right)+\sin\left(2x\right)$
$x+3>6$
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