$-\left(2\right)^2-2+3$
$y'=2+y-y^2$
$\left(-3\right)-\left(-16\right)$
$\int-\frac{7}{4t\sqrt{16t^2-36}}dt$
$a+\frac{1}{3}-\frac{1}{a+3}=0$
$\sqrt{x-10}=5$
$12^2\:x\:2\:+\:\:\frac{40}{5}\:-6^2\:+\:9$
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