$10x^2+8=6y^3+4$

$9x^2+12x=4$

$3x^2-2x+6$

$6x^4+11\:x^3-30\:x^2-29x-6$

$\frac{2x^{3\:}}{\left(9-x^2\right)}$

$\int\left(\left(1-\frac{1}{x}\right)\cdot\left(\left(1+\frac{1}{x^2}\right)\right)\right)dx$

$\int_0^{\infty}\left(\frac{1}{\left(1+x\right)^{\frac{1}{4}}}\right)dx$