$\lim_{x\to2}\left(\frac{-3x^2+2x-8}{x-2}\right)$
$4x^{2}=1$
$a\left(x^2+9\right)+\left(bx+c\right)\left(x-1\right)$
$8x\:-\:4\left(x\:+\:8\right)\:=\:8$
$\int\left(\cos\right)^2\frac{1}{2}xdx$
$\left(2a-4\right)\:=4$
$\int\frac{1}{\left(9+25x^2\right)^{\frac{3}{2}}}dx$
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