$4x+\frac{x}{2}-5$
$4x+17=x-4$
$17\left(-33\right)$
$\sin42=\frac{5}{3\left(x\right)}$
$y'\:=\:xy\:-\:x\:+2y-2$
$9y^2-12y+1$
$5-\left(-12\right)-8+6-\left(+5\right)+10-5\left(-9\right)$
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