$3x\:.\:x$
$\left(x+2b\right)^2$
$36x^4y^2-100$
$x\left(x+2\right)\left(x+7\right)$
$-\sqrt{12}$
$4x^2-9y^2-8x-36y-68=0$
$\frac{2s^2+6}{s^4+5s^3+2s^2}$
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