$\frac{a}{b}\sqrt{\frac{16}{25}}$
$x^3+2\ge0$
$\int\left(\frac{1}{\left(y^2+1\right)}\right)dy$
$\sqrt[4]{16m^4}$
$\frac{dy}{dx}=6x^2\left(2+y\right)$
$\left(1.5\right)^2-3\left(1.5\right)+1$
$\tan\left(x\right)^2=\frac{\sec\left(x\right)^2}{\csc\left(x\right)^2}$
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