$\int16ln8xdx$
$x^2-1\ge0$
$\lim_{x\to\infty}\left(2xe^x\right)$
$\frac{d}{dx}x^3-x^2-36x+36$
$\frac{16x^4}{y^2}-\frac{25}{x^2}$
$\int3e^{x^2}dx$
$\int3x\cdot ln\left(x^2+3\right)dx$
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