$\frac{z^2}{4}+y+4y^2$
$12,3\cdot12,746$
$-28-\left(-8\right)$
$28+6-2,5\:kg+34$
$2x^2-10\cdot5x+6\cdot125$
$\left[\left(3-6\right)^2\right]\:\left(4^2\right)-3$
$\left(1-1\right)^x$
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