$\frac{x^2-4x-12}{x+3}$
$\log_{10}\left(x\right)=\log_{10}\left(x\right)+.2$
$x^2-3x-20\le0$
$m+2\ge5$
$\frac{16y^7-24y^5}{8y^2}$
$\frac{x^2y^2-1}{xy+1}$
$\left(3m^2-7\right)^2$
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