$1x^4$
$-3^4\cdot\left(-2\right)^6$
$6x^2+3y^2=12$
$\frac{d}{dx}\:\sin^{-1}\sqrt{2t}$
$3\left(-14\right)+\left(-4\right)\left(-3\right)-4\left(6\right)$
$\lim_{x\to\infty}\left(1+\frac{1}{3x+1}\right)^{5x+2}$
$\frac{2x^2+3}{x^2-1}$
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