$y'+x=0$
$\int_{-3}^6\left(\frac{x-3}{x^2-3x-28}\right)dx$
$1+\cot\tan^2a=\csc^2a$
$\left(2x+m\right)^3$
$2\left(-4y^2+2xy+\left(x+2y\right)^2\right)$
$x\:5\:\:\:\:+\:\:\:x\:4\:\:\:\:\:\:\:$
$7\left(4x+y\right)+7y$
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