$\frac{40}{\frac{\:2}{5}}$
$\left(x^{-4}z^5\right)\left(\frac{3xu^3}{z^{-1}}\right)^{-2}$
$\int x\sqrt[7]{1-x}dx$
$\frac{-3}{5}=\frac{1}{5}$
$\left(2x-y\right)\left(2x+4\right)\left(4x^2+y^2\right)^2$
$\frac{dy}{dx}\:=4x-5$
$4^2-4\left(3-4\right)$
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