$8\cdot\tan\left(x\right)=3\cdot\cos\left(x\right)$

$\frac{d}{dx}\left(2x^2y^2+5x^3y^3=4x^2y^2\right)$

$\int_{-\frac{2}{3}}^{\frac{1}{3}}\left(2-3x\right)^{-\frac{1}{2}}dx$

$\log_{10}\left(x^2+x\right)=\log_{10}\left(x-4x\right)$

$\left(30+x\right)=2\left(10+x\right)$

$2m+4m-3m^2$

$\frac{d}{dx}-3xy^2=6$