$3x^3+9x^2+6x$
$13.000-4000$
$\frac{36m^2-9}{6m+3}$
$\frac{+x^{2}-4}{2x+2}\cdot\frac{x+3}{x-1}$
$\left(x^2\right)\left(2x^3+x\right)^2$
$n-5=3n+25$
$\left(-6x^2\right):\left(x^2-x+3\right)$
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