$13\sin\left(x\right)+6=sin\left(x\right)$
$\left(4x^3+3x+5x^2+9\right)+\left(4x^4-3x^3+2x^2-x-9\right)$
$x^2+x<x+2$
$3x\left(x-2\right)+x^2$
$\frac{dy}{dx}=\frac{x^2}{2x^2+2y^2-xy}$
$\:\frac{-56}{8}$
$\frac{1}{a+6}+\frac{3}{a+4}=\frac{-2}{a^2+10a+24}$
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