$4+\left(-2\right)-\left(-3\right)-6$
$\frac{d}{dx}y^5-2xy^2+4x$
$b+b+b+b$
$\sqrt[4]{625.3^4}.\left(-1\right)^{17}.\left(-2\right)^5$
$\left(2+tan\:x\right)^2$
$\int\frac{x^3}{\left(x^2-2x+1\right)}dx$
$\frac{3}{5}=\frac{x-6}{x}$
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