$1-19-45-134$
$\frac{3\left(8\right)}{4-2^2}$
$-8\cdot4+9$
$x^2+8x-3=0$
$3x+1\ge-4-2x$
$\frac{2x+4}{2x-4}$
$4x^4y^2\cdot4y^3z^3$
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