$\frac{4.9}{3.4\:}=\frac{29.4}{23.8}$
$-8-2y+3y=17$
$\left(4x^2y\right).\left(3xz^2\right)$
$\frac{dy}{dx}=\left(2-3x\right)^4$
$\left(\left(\frac{1}{cosx}\right)-1\right)\left(\left(\frac{1}{cosx}\right)+1\right)$
$2\sqrt{81}$
$\frac{2}{5}=\frac{x}{10}$
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