$\left(3m-\frac{1}{3}\right)^2$
$\frac{4d^4+8d^3+10d^2}{2d}$
$\frac{d}{dx}2^y$
$5m+20=40$
$m-4=12$
$\left(1-5i\right)\left(2+6i\right)$
$b\left(x+1\right)+6\left(x+2\right)=7\left(x+3\right)$
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