$2x^3y-8x^2y^2-6xy^3$
$\lim\:_{x\to\:32}\left(\frac{1+6x}{1+2x}\right)^{\frac{1}{x}}$
$x+\:\frac{4}{x}=-2$
$\lim_{x\to0}\left(\frac{\sin\left(6x^{12}\right)}{2x^{12}}\right)$
$\frac{dy}{dx}=\frac{4+11x}{xy^2}$
$\frac{4}{2x+8}=\frac{6}{x-10}$
$v^2+20v=-7$
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