$\frac{x^2+\frac{1}{4}x-3}{x+2}$
$\left(7w-m\right)^2$
$3sin\left(2x\right)=tan\left(x\right)$
$\left(7wx^2-8x^4y^3\right)\left(7wx^2+8x^4y^3\right)$
$\lim_{x\to\infty}4x^3+2x$
$y^2\left(2x^2-7x+3\right)$
$\int tan5\theta d\theta$
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