$x^2\:\ge6\:-\:x$
$\frac{x^4-2x^3-15x^2+55x-270}{x-5}$
$\left(9+4m\right)^4$
$\left(3x-8y\right)^3$
$\frac{dy}{dx}=\frac{xe^{2x+y^5}}{y^4}$
$\frac{x^3+4x^2-x-4}{x+4}$
$\sqrt{5}.\sqrt{10}$
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