$12x^2-96x+144$
$\left(x-1\right)\left(x+9\right)\le0$
$tan^3\left(x\right)cosec^3\left(x\right)$
$\frac{x^{2}-4x}{x^{2}-8x+16}$
$\frac{\left(2x^4+4x\right)}{x-2}$
$\frac{3y^2}{2x^{-4}}y^2$
$5x-12=36-x$
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