$2+\sqrt{x+8}=\sqrt{3x+12}$
$g\left(x\right)=\frac{x-1}{4\left(1\right)^{2}+5x-14}$
$-4x^2+x+3$
$\left(2x-1\right)\cdot dx+\left(5y+7\right)\cdot dy=0$
$\int\left(x^3\cdot\sqrt{3x^2+1}\right)dx$
$x^2dx=\left(-xy\:+\:2x^2+2y^2\right)dy$
$3\left(2x+3\right)+2\left(3x+2\right)$
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