$2x-5<x-6$
$u^2=\frac{25}{81}$
$x^3-x^2+2$
$2x^2=12$
$\lim_{x\to\infty}\left(\frac{tan\left(3x\right)}{3x}\right)$
$\frac{\left(12-5x\right)}{6-5x-x^2}$
$\left(2x^2\:-\:3\right)\:\left(2x^3\:-\:3x^2\:+\:4x\right)$
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