$81\cdot45$
$40m^4m^2-48m^2n^3x^2-72m^3n^4$
$6x^2y\cdot7xy^2$
$\sqrt{53}\left(53-22\right)\left(53-41\right)\left(53-43\right)$
$\int\frac{12}{x^3+4x}dx$
$y'+\frac{y}{x}=\log\left(x\right)+1$
$\left(5m^{a+3}+6n^{2b-4}\right)^2$
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