$\frac{2}{2\sqrt{2x}}+\frac{2}{3\sqrt[3]{2x^2}}$
$eqeqe+21$
$\left(\frac{a^{-8}}{b^{11}}\right)^{-2}$
$\frac{dy}{dx}\left(x^2+4xy-y^3=11\right)$
$\left(16-9\right)-\left(7-10\right)$
$x^2+25x-1236=0$
$16x^2+16xy+4y^2$
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