$2-3\sin^2x=3\cos^2x-1$
$\left(\frac{m}{n^3}\right)^5.\left(\frac{m}{n}\right)^{-3}$
$\int\left(\frac{2x-1}{4x+2}\right)dx$
$\sqrt[5]{9^5}$
$\left(-8ab^4c+2x^3+12x^4y^5\right)$
$x^2+x-6>0$
$\int\left(6^{-3x}\right)dx$
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