$2\left(4\right)-7$
$\left(-114\right)^2$
$\lim_{x\to-1}\left(\frac{27a^3+8b}{3a+2b}\right)$
$\left(2p-3q\right)^7$
$\frac{xy}{a}-\frac{1}{b}$
$xy'=180y$
$\lim_{x\to\infty}\left(\frac{3x^3}{x^2+1}\right)$
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