$\left(3x\right)\left(y^2\right)^2$
$\left(-19\right)\:-\:\left(-13\right)\left(-19\right)\:-\:\left(-13\right)$
$x^2-28+49$
$\lim_{x\to1}\left(\frac{\sqrt[3]{1+x}-1}{x}\right)$
$\cot^{2}u+1=\frac{1}{\sen^{2}u}$
$ab^2-b^4$
$x-12^2$
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