$2\log\left(x\right)+\log\left(4\right)=16$
$x^6=27$
$-2x^2;x=3$
$\int\:9x\:e^{7x}\:dx$
$\lim_{x\to\infty}\left(\frac{ln\left(x^2\right)}{ln\left(3x\right)}\right)$
$\frac{d}{dx}1-x^2$
$\sqrt[7]{\left(x^2+4\right)}^6$
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