$\lim_{x\to0}\left(\frac{14^x-4^x}{x}\right)$
$\lim_{n\to\infty}\left(\sqrt{n+1}-4\right)$
$\left(-6x-5\right)\left(-2x+3\right)$
$\left(y+1\right)dx-xdy=0$
$x^2\left(x+7\right)+3x\left(x+7\right)-4x-28$
$482+230$
$5mx+2=3m+x$
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