$2\sin\left(3x\right)\cos\left(x\right)-\sin\left(4x\right)$

$16x^2+9y^2-96x=-288$

$\sqrt{144}+2\cdot3^2$

$\frac{1}{1+cos\:x}-\frac{1}{1-cosx}=2cos\:x\:csc^2$

$10x\:-\:6\:+\:x$

$\frac{\cos\left(2a\right)}{cos\left(a\right)-sin\left(a\right)}$

$\left(-3\right)\cdot\sqrt[20]{16^5}-\left(-2\right)^5$