$\int\frac{\left(t^5\right)}{\left(t^3+1\right)^2}dt$
$\:0.02w+w-0.11w$
$3x+10<1$
$5 \cdot ( 4 + 3 )$
$2\cdot3^3+3\cdot4^2-17$
$7\left(1-2x\right)+10x-9>x+13$
$\int\sec^2\left(x\right)+3x-4\:dx$
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