$20x^2-4x-8$
$\lim_{x\to3}\left(\frac{\sqrt[3]{x^3+1}}{\sqrt{\left(x-1\right)^2}}\right)$
$\frac{d}{dx}-4x$
$4x^2\:+\:5x^2\:+\:x^2\:+\:7x^2$
$15x^2=20$
$x+3x+6xy-2y$
$7-\:\left(-12\right)$
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