$\left(3x^2\right)^{\frac{2}{5}}$
$-2\:+480$
$12\sec\left(x\right)+2=-10$
$\frac{5}{7}=\frac{75}{x}$
$\int_{-5}^{-3}\left(\frac{-1}{5x+2}\right)dx$
$5-3-1$
$3x+3>5x-3$
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