$\int\frac{\left(3x+1\right)}{x^3+4x^2-5x}dx$
$\frac{d^3}{dx^3}\left(\frac{-2}{3}x^3+3x^2+\frac{3}{10}x^5-3\right)$
$-\sqrt{49}+3\cdot5-10$
$-5\left(3n+3\right)+9\left(-7+n\right)$
$x^2-15x+6.25$
$15a^2-6ab-8a^2+20-5ab-31+a^2+9ab$
$-5+7-\left(2+3\cdot\left(-3\right)\right)$
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