$\:x^8-1$
$\frac{1}{16x^3+4x^2}$
$5\:.\:11^{-8}\:.\:11^7$
$\left(q+1\right)dc=cqdq$
$\left(2\left(2\right)^3-4\right)-\left(2\left(1\right)^3-4\right)$
$-8x^2-20x+48\ge0$
$81b^2-36a^2$
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