$\cot\left(m\right)\tan\left(m\right)=1$
$x^4+1-2^2$
$\lim_{x\to0}\left(\frac{e^{3x-5}}{4x}\right)$
$\lim_{x\to0}\left(\frac{x}{2x-1}\right)^x$
$\lim_{x\to2}\:x^2-5$
$\left(4m+5n-2g\right)^2$
$-4x=-24$
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