$\lim_{x\to4}\left(\frac{x-4}{x^2-1}\right)$
$\left(4xy^3+3xy^2\right)^3$
$\left(x^2+4\right)dy=\left(2y+8xy\right)dx$
$\frac{dy}{dx}=-2x\cdot\left(y-3\right)$
$\sqrt{5}+3^2$
$\frac{n}{-2}>4$
$\left(3x^2-7\right)^4$
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