$\:5x^4y+2x^3y^3$
$\lim_{x\to-\frac{1}{3}}\left(\frac{4x^3-5x^2-3x}{5x^3+3x^2}\right)$
$lny=ln\left(\left(4\right)^{\frac{4}{x}}\right)$
$-19x-19=-19x+19$
$f\left(x\right)=\sqrt[3]{\frac{\left(3x+2\right)^2}{\left(2-x^2\right)^5}}$
$x^2=-121$
$\cot^2x\sec^2x-1=1$
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