$2x+4\ge12$
$2x-5y\:=\:10\:$
$2y-8x+6=0$
$\frac{4-x^2}{x+1}$
$\:\:\:\:\lim_{x\to0}5\left(\frac{\tan\left(6x\right)}{\tan\left(8x\right)}\right)$
$\frac{dy}{dx}=\frac{x^5y}{\left(lny\right)^5}$
$5\cos2x-\cos x+3$
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