$\int\:\:6\:x\sqrt{1-3\:x^2}dx$
$\frac{x^3-6}{x+2}$
$\left(\frac{2}{3}x+4\right)\left(\frac{2}{3}x-8\right)$
$39a^2-18a^2$
$\sin x=-0.81$
$\:12v\:+\:12\:-\:8v\:+\:\left(-4\right)$
$y=\frac{1}{16}\text{cdot x}^4$
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