$\int\left(x+7\right)^6dx$
$\left(2x^2-10x\right)$
$sin4x=0$
$x^2+6x-16$
$3x+7>1$
$x-4=2$
$\frac{d}{dx}\left(\frac{\left(x+1\right)\left(x-2\right)}{x-3}\right)$
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