$3x^2-8x=11$
$8x^2y^3+8xy-6x^2y^2z-6xz$
$x^2-8\le0$
$16m^2-40mn+25n^2$
$\left(a^2-4b\right)^4$
$6+b-4-2b^2-4b^2+4b$
$\lim_{x\to\infty}\left(\frac{3x}{1\cdot ln\left(1+2e^x\right)}\right)$
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