$\lim_{x\to-1}\left(\frac{x^3-3x+3}{\left(x+1\right)^2}\right)$
$\lim_{x\to\infty}\left(-3x^2+115x+100\right)$
$3\ln\left(e^5\right)$
$x^2+18x+20$
$\frac{\left(2x+6\right)}{\left(x-1\right)}$
$\left(2ab-c\right)\left(2ab+c\right)$
$\int\frac{x^2}{9}dx$
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