$y'+\frac{1}{6}y=e^{-2x}+8$
$\int_{-1}^1e^{-x}cosxdx$
$\log\left(10+2x\right)=2\log\left(x+1\right)$
$\int6x^2\arcsin\left(2x\right)dx$
$\left(\frac{2}{3}x+4\right)\left(\frac{2}{3}x-8\right)$
$\left(2x^5\right)^4$
$0<x^2-7x+10$
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